How do you solve the following system: #-5x + 3y= 6, 8x-3y=3 #?

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Answer 1 · 2018-04-22T12:14:39

#x = 3#
#y = 7#

Add the two equations together to cancel the #3y# and #-3y#:

#" " -5x + 3y = 6#

#"+ " ( 8x - 3y = 3)#

#-> -5x + 8x + 3y + (-3y) = 6 + 3#

# 3x = 9#

# x = 3#

Substitute #x# into one of the equations:

#8x-3y = 3#

#8(3)-3y = 3#

#24 - 3y = 3#

#-3y = -21#

# y = 7#