How do you solve #9x-4y = -59# and #4x+27 = y# using substitution?

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Answer 1 · 2016-08-26T15:13:37

#x=-7# and #y=-1#

We have the first equation as #9x-4y=-59# and second equation #4x+27=y#.

The second equation gives #y=4x+27# and substituting this value of #y# in first we get

#9x-4(4x+27)=-59# or

#9x-16x-108=-59# or

#-7x=-59+108=49# or

#x=-7# and

#y=4×(-7)+27=-28+27#

or #y=-1#