How do you solve $4 x + 3 y = - 5$ $4x+3y=-5$ and $x - y = - 3$ $x-y=-3$ using substitution?

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How do you solve $4 x + 3 y = - 5$ $4x+3y=-5$ and $x - y = - 3$ $x-y=-3$ using substitution?

1 Answer

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Answer 1 · 2016-07-11T16:40:55

$x = - 2 and y = 1$ $x=-2 and y = 1$

Explanation:

In this answer, I have subbed in for x. A solution that subbed in for y would be equally valid (and might be instructive for you to do to check you get the same answer!).

Rearrange the second equation to obtain:

$x = y - 3$ $x = y - 3$

Sub this into the first expression:

$4 (y - 3) + 3 y = - 5$ $4(y-3) + 3y = -5$

$4 y - 12 + 3 y = - 5$ $4y - 12 + 3y = -5$

$7 y = 7 \Rightarrow y = 1$ $7y = 7 implies y = 1$

$x = y - 3 = 1 - 3 = - 2$ $x = y - 3 = 1 - 3 = -2$

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How do you solve $4 x + 3 y = - 5$ $4x+3y=-5$ and $x - y = - 3$ $x-y=-3$ using substitution?

1 Answer

Explanation:

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1 Answer

Explanation:

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How do you solve $4 x + 3 y = - 5$ $4x+3y=-5$ and $x - y = - 3$ $x-y=-3$ using substitution?