How do you solve #4x+3y=-5# and #x-y=-3# using substitution?

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How do you solve #4x+3y=-5# and #x-y=-3# using substitution?

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Answer 1 · 2016-07-11T16:40:55

#x=-2 and y = 1#

Explanation:

In this answer, I have subbed in for x. A solution that subbed in for y would be equally valid (and might be instructive for you to do to check you get the same answer!).

Rearrange the second equation to obtain:

#x = y - 3#

Sub this into the first expression:

#4(y-3) + 3y = -5#

#4y - 12 + 3y = -5#

#7y = 7 implies y = 1#

#x = y - 3 = 1 - 3 = -2#

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How do you solve #4x+3y=-5# and #x-y=-3# using substitution?

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