How do you solve the following system?: 2x + 7y = -8, -x-8y=32 2x+7y=8,x8y=32

1 Answer
Apr 25, 2016

x=160/9x=1609 and y=-56/9y=569.

Explanation:

The equations are 2x+7y=-82x+7y=8 --(A) and -x-8y=32x8y=32 -- (B)

Now multiplying (B) by 22 and adding to (A) cancels out xx, and we get

7y-16y=-8+647y16y=8+64 or -9y=569y=56 or y=-56/9y=569. Now putting this in (B), we get

-x-8xx-56/9=32x8×569=32 or -x+448/9=32x+4489=32 or -x=32-448/9=288/9-448/9=-160/9x=324489=28894489=1609 or x=160/9x=1609