How do you solve the following system?: $2 x + 7 y = - 8, - x - 8 y = 32$ $2x + 7y = -8, -x-8y=32$

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How do you solve the following system?: $2 x + 7 y = - 8, - x - 8 y = 32$ $2x + 7y = -8, -x-8y=32$

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Answer 1 · 2016-04-25T16:57:12

$x = \frac{160}{9}$ $x=160/9$ and $y = - \frac{56}{9}$ $y=-56/9$ .

Explanation:

The equations are $2 x + 7 y = - 8$ $2x+7y=-8$ --(A) and $- x - 8 y = 32$ $-x-8y=32$ -- (B)

Now multiplying (B) by $2$ $2$ and adding to (A) cancels out $x$ $x$ , and we get

$7 y - 16 y = - 8 + 64$ $7y-16y=-8+64$ or $- 9 y = 56$ $-9y=56$ or $y = - \frac{56}{9}$ $y=-56/9$ . Now putting this in (B), we get

$- x - 8 \times - \frac{56}{9} = 32$ $-x-8xx-56/9=32$ or $- x + \frac{448}{9} = 32$ $-x+448/9=32$ or $- x = 32 - \frac{448}{9} = \frac{288}{9} - \frac{448}{9} = - \frac{160}{9}$ $-x=32-448/9=288/9-448/9=-160/9$ or $x = \frac{160}{9}$ $x=160/9$

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How do you solve the following system?: $2 x + 7 y = - 8, - x - 8 y = 32$ $2x + 7y = -8, -x-8y=32$

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following system?: 2x+7y=−8,−x−8y=32 2x + 7y = -8, -x-8y=32

1 Answer

Explanation:

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Impact of this question

How do you solve the following system?: $2 x + 7 y = - 8, - x - 8 y = 32$ $2x + 7y = -8, -x-8y=32$