How do you solve the following system?: 2x + 7y = -8, -x-8y=32 Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Shwetank Mauria Apr 25, 2016 x=160/9 and y=-56/9. Explanation: The equations are 2x+7y=-8 --(A) and -x-8y=32 -- (B) Now multiplying (B) by 2 and adding to (A) cancels out x, and we get 7y-16y=-8+64 or -9y=56 or y=-56/9. Now putting this in (B), we get -x-8xx-56/9=32 or -x+448/9=32 or -x=32-448/9=288/9-448/9=-160/9 or x=160/9 Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve y=-6x-3 and y=3 using the substitution method? How do you solve 12y-3x=-1 and x-4y=1 using the substitution method? Which method do you use to solve the system of equations y=1/4x-14 and y=19/8x+7? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve x+y=5 and 3x+y=15 using the substitution method? What is the point of intersection of the lines x+2y=4 and -x-3y=-7? See all questions in Systems Using Substitution Impact of this question 1339 views around the world You can reuse this answer Creative Commons License