How do you solve the following system?: $-x -y =2, x -y = -1$

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Answer 1 · 2018-04-21T09:02:10

Lettuce solve for $y$
$1^(st)$ equation
$-x-y=2$
$-y=2+x$
$color(red)(y=-2-x$

$2^(nd)$ equation
$x-y=-1$
We already know $-y$
$x+2+x=-1$
$2x=-1-2$
$2x=-3$
$x=-3/2$
$color(red)(x=-1.5$
$y=-2-x$
$y=-2-1.5$
$color(red)(y=-0.5$

How do you solve the following system?: -x -y =2, x -y = -1-x -y =2, x -y = -1