How do you solve #6x + 2y = 2# and #5x - 7y = 6#?

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Answer 1 · 2017-07-05T08:19:09

Multiply the first equation by 7 and the second equation by 2.

When you multiply the first equation by 7 and the second by 2:

#42x + 14 y = 14#
#10x - 14 y = 12#

Combine these two, yielding:

#52x = 26#

#x=1/2# This is your x. When you put this value in the first equation

#6times(1/2) + 2y= 2#

#3 + 2y = 2#

#2y = 2-3#

#2y = -1#

#y=-1/2#

This is your y.

Your solution: #x=1/2# and #y=-1/2#