How do you solve the system #x = 2y + 6# and 3x = -2y + 10##?

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Answer 1 · 2016-06-04T21:56:29

x=4 and y=-1

you would do this by solving by addition/elimination.

#x=2y+6# plus
#3x=-2y+10#

add all terms going in a downward direction. #x+3x=4x#, #2y-2y=0# and #6+10=16#, leaving

#4x=16#

#:.x=4#

sub the x value in and test for y.

#4=2y+6#

#-2=2y#

#y=1#

.

#3(4)=-2y+10#

#12=-2y+10#

#2=-2y#

#y=1#