How do you solve the linear equation x=y+3 and 3x-2y=4 using the substitution method and are they dependent, independent, or inconsistent?

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Answer 1 · 2016-02-06T14:22:45

$x = - 2$ $x=-2$ and $y = - 5$ $y=-5$
independent

from the given
$x = y + 3$ $x=y+3$ first equation
and $3 x - 2 y = 4$ $3x-2y=4$ second equation

Use first equation in to the second equation

$3 (y + 3) - 2 y = 4$ $3(y+3)-2y=4$

$3 y + 9 - 2 y = 4$ $3y+9-2y=4$
$3 y - 2 y = 4 - 9$ $3y-2y=4-9$

$y = - 5$ $y=-5$

go back to thr first equation use $y = - 5$ $y=-5$

$x = y + 3$ $x=y+3$
$x = - 5 + 3$ $x=-5+3$
$x = - 2$ $x=-2$

independent system of equations

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