How do you solve the following system: $x-2y=4, 2x-y=7$ ?

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How do you solve the following system: $x-2y=4, 2x-y=7$ ?

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Answer 1 · 2018-03-15T20:34:16

$(x, y) = (10/3, -1/3)$

Explanation:

First, define one variable (let's do x) in terms of the other (y). Using the first equation, we can conclude that $x=2y+4$ . Then, we can substitute $2y+4$ into anywhere we see x in the second equation, so:
$2(2y+4) - y = 7$
$4y+8-y=7$
$3y+8=7$
$3y=-1$
$y=-1/3$
Then, plug y back into the first equation to find x.
$x-2(-1/3) = 4$
$x+2/3 = 4$
$x = 10/3$

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How do you solve the following system: $x-2y=4, 2x-y=7$ ?

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How do you solve the following system: x-2y=4, 2x-y=7 x-2y=4, 2x-y=7 ?

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Explanation:

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How do you solve the following system: $x-2y=4, 2x-y=7$ ?