How do you solve the following system: 6x + y = 2, 2x + 3y = 346x+y=2,2x+3y=34?

1 Answer
Mar 25, 2018

x=-7/4x=74
y= 25/2y=252

Explanation:

Solve using substitution:
6x+y=26x+y=2
2x+3y= 342x+3y=34

The first equation when solved for yy:
y=-6x+2y=6x+2

Substitute for yy into the second equation:
2x+3(-6x+2)= 342x+3(6x+2)=34

Distribute:
2x-18x+6= 342x18x+6=34

Combine like terms:
-16x+6= 3416x+6=34

Solve for x:
-16x=2816x=28
x=28/-16x=2816
x=-7/4x=74

Solve for y by plugging in for xx:
y=-6(-7/4)+2y=6(74)+2
y= 42/4+2y=424+2
y= 21/2+4/2y=212+42
y= 25/2y=252