How do solve the following linear system?: $x-2y = -3 , 5x - 3y = -29$ ?

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Answer 1 · 2016-04-29T14:18:57

$x=-7, y=-2$

$x-2y=-3$
$5x-3y=-29$

Rearrange the first equation to get $x$ by itself on the left hand side
$x=2y-3$

Then substitute for $x$ in the second equation.
$5(2y-3) -3y = -29$
$10y-15-3y=-29$
$7y = -29+15 = -14$
$:.y=-2$

Substituting back into the reformatted first equation gives
$x=2(-2)-3$

$:.x= -7$

How do solve the following linear system?: x-2y = -3 , 5x - 3y = -29 x-2y = -3 , 5x - 3y = -29 ?