How do solve the following linear system?: $x = y - 11, 8 x + 3 y = - 9$ $x= y - 11 , 8x + 3y= -9$ ?

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How do solve the following linear system?: $x = y - 11, 8 x + 3 y = - 9$ $x= y - 11 , 8x + 3y= -9$ ?

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Answer 1 · 2016-01-05T06:38:14

$x = - \frac{42}{11} and y = \frac{79}{11}$ $x=-42/11 and y=79/11$

Explanation:

$x = y - 11$ $x=y-11$
$implies x-y=-11...............(i)$
$8x+3y=-9........(ii)$
Multiply $(i)$ by $3$ and add in $(ii)$
$implies 3x-3y=-33$
$+8x+3y=-9$
By addition we have
$11x=-42$
$implies x=-42/11$
Put $x=-42/11$ in $(i)$
$implies -42/11-y=-11$
$implies -42-11y=-121$
$implies 11y=79$
$implies y=79/11$

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How do solve the following linear system?: $x = y - 11, 8 x + 3 y = - 9$ $x= y - 11 , 8x + 3y= -9$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do solve the following linear system?: x= y - 11 , 8x + 3y= -9 x=y−11,8x+3y=−9 x= y - 11 , 8x + 3y= -9 ?

1 Answer

Explanation:

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How do solve the following linear system?: $x = y - 11, 8 x + 3 y = - 9$ $x= y - 11 , 8x + 3y= -9$ ?