How do solve the following linear system?: $x+y=-4, 2x + 4y = 8$ ?

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How do solve the following linear system?: $x+y=-4, 2x + 4y = 8$ ?

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Answer 1 · 2018-08-04T11:47:23

$x=-12 and y=8$

Explanation:

Here ,

$x+y=-4$

$:.y=-x-4.....to(1)$

$2x+4y=8...........to(2)$

Subst. $y=-x-4$ into $(2)$ , we get

$2x+4(-x-4)=8$

$:.2x-4x-16=8$

$:.-2x=16+8$

$:.-2x=24$

$:.color(blue)(x=-12$

Subst. $x=-12$ into $(1)$

$y=-(-12)-4=12-4$

$:.color(blue)(y=8$

Hence , $x=-12 and y=8$

Answer 2 · 2018-08-04T11:49:19

$x=-12$
$y=8$

Explanation:

$x+y=-4$ so $x=-4-y$

Substitute this into the second equation

$2x+4y=8 =>2(-4-y)+4y=8$

Multiply out the bracket

$-8-2y+4y=8$

Add 8 to both sides

$2y=16$

Divide by 2

$y=8$

Now put $y=8$ into $x+y=-4$

$x+8=-4$

Subtract 8 from both sides

$x=-12$

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How do solve the following linear system?: $x+y=-4, 2x + 4y = 8$ ?

2 Answers

Explanation:

Explanation:

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Science

Math

Humanities

... and beyond

How do solve the following linear system?: x+y=-4, 2x + 4y = 8 x+y=-4, 2x + 4y = 8 ?

2 Answers

Explanation:

Explanation:

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Impact of this question

How do solve the following linear system?: $x+y=-4, 2x + 4y = 8$ ?