How do you solve 3x+y=163x+y=16 & 2x-3y=-42x3y=4 using substitution?

1 Answer
Sep 5, 2016

x = 4, y = 4x=4,y=4

Explanation:

We have: 3 x + y = 163x+y=16 and 2 x - 3 y = - 42x3y=4

Let's solve the first equation for yy:

=> y = 16 - 3 xy=163x

Then, let's substitute this value of yy into the second equation:

=> 2 x - 3 (16 - 3 x) = - 42x3(163x)=4

=> 2 x - 48 + 9 x = - 42x48+9x=4

=> 11 x = 4411x=44

=> x = 4x=4

Now, let's substitute this value of xx into the equation for yy:

=> y = 16 - 3 (4)y=163(4)

=> y = 16 - 12y=1612

=> y = 4y=4

Therefore, the solutions to the system of equations is x = 4x=4 and y = 4y=4.