How do you solve 3x+y=16 & 2x3y=4 using substitution?

1 Answer
Sep 5, 2016

x=4,y=4

Explanation:

We have: 3x+y=16 and 2x3y=4

Let's solve the first equation for y:

y=163x

Then, let's substitute this value of y into the second equation:

2x3(163x)=4

2x48+9x=4

11x=44

x=4

Now, let's substitute this value of x into the equation for y:

y=163(4)

y=1612

y=4

Therefore, the solutions to the system of equations is x=4 and y=4.