How do solve the following linear system?: $x-2y=8 , 4x=-11+y$ ?

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How do solve the following linear system?: $x-2y=8 , 4x=-11+y$ ?

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Answer 1 · 2016-01-03T19:48:39

I found:
$x=-30/7$
$y=-43/7$

Explanation:

We can isolate $x$ from the first equation and substitute into the second to find $y$ :
$x=8+2y$
So:
$4(8+2y)=-11+y$
$32+8y=-11+y$
$7y=-43$
$y=-43/7$
We use this value back into the first equation:
$x=8+2(-43/7)=(56-86)/7=-30/7$

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How do solve the following linear system?: $x-2y=8 , 4x=-11+y$ ?

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How do solve the following linear system?: x-2y=8 , 4x=-11+y x-2y=8 , 4x=-11+y ?

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Explanation:

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How do solve the following linear system?: $x-2y=8 , 4x=-11+y$ ?