How do solve the following linear system?: # x-2y=8 , 4x=-11+y #?

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How do solve the following linear system?: # x-2y=8 , 4x=-11+y #?

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Answer 1 · 2016-01-03T19:48:39

I found:
#x=-30/7#
#y=-43/7#

Explanation:

We can isolate #x# from the first equation and substitute into the second to find #y#:
#x=8+2y#
So:
#4(8+2y)=-11+y#
#32+8y=-11+y#
#7y=-43#
#y=-43/7#
We use this value back into the first equation:
#x=8+2(-43/7)=(56-86)/7=-30/7#

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How do solve the following linear system?: # x-2y=8 , 4x=-11+y #?

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