How do you solve the following system: #x = 4 – 2y , 2x-3y=-13#?

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Answer 1 · 2015-12-13T03:16:05

The solution for the system of equations is

#color(blue)(x=-2,y=3#

#x=color(blue)((4-2y)#...........equation #(1)#

#2x-3y=-13#.....equation #(2)#

Solving by substitution:

#2x-3y=-13#

#2 * color(blue)((4-2y))-3y=-13#

#8-4y -3y=-13#

#8-7y=-13#

#-7y=-13-8#

#y=(-21)/(-7)#

#color(blue)(y=3#

Finding #x# by substituting #y# in equation #1#

#x=4-2y#

#x=4-2 * color(blue)(3#

#x=4-6#

#color(blue)(x=-2#