How do you solve the following system?: # 2x - 4y = 5 , 3x + 2y = 3 #

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Answer 1 · 2018-05-09T04:05:52

#color(green)(x = 11/8, y = -9/16#

#2x - 4y = 5, " Eqn (1)"#

#3x + 2y = 3, " Eqn (2)"#

#6x + 4y = 6, " Eqn (2) * 2"#

#"Adding Eqn (1) with (2 * Eqn (2))"#

#8x = 11#

#color(green)(x = 11/8#

Substituting value of x in Eqn (1),

#(2 * 11)/8 - 4y = 5#

#-4y = 5 - 22/8 = 9/4#

#color(green)(y = - 9/16#