How do you solve the following system?: $2 x - 4 y = 5, 3 x + 2 y = 3$ $2x - 4y = 5 , 3x + 2y = 3$

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Answer 1 · 2018-05-09T04:05:52

$x = \frac{11}{8}, y = - \frac{9}{16}$ $color(green)(x = 11/8, y = -9/16$

$2 x - 4 y = 5, Eqn (1)$ $2x - 4y = 5, " Eqn (1)"$

$3 x + 2 y = 3, Eqn (2)$ $3x + 2y = 3, " Eqn (2)"$

$6 x + 4 y = 6, Eqn (2) * 2$ $6x + 4y = 6, " Eqn (2) * 2"$

$Adding Eqn (1) with (2 * Eqn (2))$ $"Adding Eqn (1) with (2 * Eqn (2))"$

$8 x = 11$ $8x = 11$

$x = \frac{11}{8}$ $color(green)(x = 11/8$

Substituting value of x in Eqn (1),

$\frac{2 \cdot 11}{8} - 4 y = 5$ $(2 * 11)/8 - 4y = 5$

$- 4 y = 5 - \frac{22}{8} = \frac{9}{4}$ $-4y = 5 - 22/8 = 9/4$

$y = - \frac{9}{16}$ $color(green)(y = - 9/16$

How do you solve the following system?: 2x−4y=5,3x+2y=3 2x - 4y = 5 , 3x + 2y = 3