How do you solve the following system?: #12x +33y =1, -4x +5y = -2#

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Answer 1 · 2018-04-16T10:40:01

By arranging the equation

#12x + 33y = 1#
#-12x + 15y = -6#

(after multiplying 3)

Now add the two equations:

#48y = -5#

#y=-5/48#

Put this value in the 1st original equation:

#12x = 1-(33times-5/48)#

#12x = 1+(165/48)#

#12x = (48+165)/48#

#12x = 213/48#

#12x = 71/16#

#x = 71/(16times12)#

#x=71/192#

Your solution:

#x=71/192#
#y=-5/48#

or

#y=-20/192#