How do solve the following linear system?: $-9x + 6y = -2 , 11x + 3y + 7 = 0$ ?

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Answer 1 · 2016-01-26T04:37:23

1) multiply the second equation by 2
$22x + 6y +14=0$

2) set the first equation equal to $0$ then make both equations equal to each other
$22x+6y+14=-9x+6y+2$

3) move everything to one side and sum it up
$31x+12=0$
$31x=-12$
$x=-12/31$

4) insert $x$ into the first equation and you get
$(-9*(-12))/31+6y=-2$
$6y=((-2*31)-9*12)/31$
$y=((-2*31)-9*12)/(6*31)$
$y=(-31-54)/93=-85/93$

How do solve the following linear system?: -9x + 6y = -2 , 11x + 3y + 7 = 0 -9x + 6y = -2 , 11x + 3y + 7 = 0 ?