How do you solve $x = 4 y$ $x=4y$ and $x = y - 3$ $x=y-3$ using substitution?

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Answer 1 · 2016-03-16T13:16:20

$x, y = - 4, - 1$ $x,y=-4,-1$

$x = 4 y, x = y - 3$ $color(blue)(x=4y,x=y-3$

Substitute the value of $x$ $x$ to the second equation

$\to 4 y = y - 3$ $rarr4y=y-3$

$\to 4 y = y = - 3$ $rarr4y=y=-3$

$\to 3 y = - 3$ $rarr3y=-3$

$\Rightarrow y = - \frac{3}{3} = - 1$ $rArrcolor(green)(y=-3/3=-1$

Substitute the value of $y$ $y$ to the first equation

$\to x = 4 (- 1)$ $rarrx=4(-1)$

$\Rightarrow x = - 4$ $rArrcolor(green)(x=-4$

$:.color(green)(|bar (ul(x,y=-4,-1)))|$

How do you solve x=4yx=4yx=4y and x=y-3 x=y−3x=y-3 using substitution?