How do you solve the following linear system $- x + y = 2, x + 3 y = 2$ $-x + y = 2 , x + 3y =2$ ?

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Answer 1 · 2018-03-17T04:03:24

$(- 1, 1)$ $(-1,1)$

We have:

$((-x+y=2),(x+3y=2))$

We can add the two equations. See how the $x$ variable cancels out, as $-x+x=0$ .

$4y=4$

$y=1$

We can input this into the first equation:

$-x+1=2$

$-x=1$

$x=-1$

So the solution is $(-1,1)$ .

Another cool way to solve these is to graph them. Their point of intersection is the solution to this system:

Desmos

How do you solve the following linear system -x + y = 2 , x + 3y =2 −x+y=2,x+3y=2-x + y = 2 , x + 3y =2 ?