How do you solve #2x+4y=6# and #2x+y= -3# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer ali ergin Mar 14, 2016 #x=-3# #y=3# Explanation: #2x+4y=6" "color(red)(2x=6-4y)# #color(red)(2x)+y=-3# #6-4y+y=-3# #-3y=-6-9# #3y=9# #y=9/3" "y=3# #2x+4(3)=6" "2x+12=6# #2x=6-12" "2x=-6# #x=-6/2# #x=-3# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1248 views around the world You can reuse this answer Creative Commons License