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How do you solve the following system: #y = 3x – 12, 2x-3y=-13#?

1 Answer

Dec 18, 2015

#color(white)(xx)x=7# and #y=9#

Explanation:

#color(white)(xx)y=3x-12, 2x-3y=-13#

#color(white)(xx)2x-3y=-13<=>y=(2x+13)/3#

#=>color(red)(3x-12)=(2x+13)/3#
#=>color(red)(3xx)(3x-12)=color(red)(3xx)(2x+13)/3#
#=>9x-36color(red)(-2x+36)=2x+13color(red)(-2x+36)#
#=>color(red)(1/7xx)7x=color(red)(1/7xx)49#
#=>x=7#

#color(white)(xx)y=3x-12#
#color(white)(xxx)=3xxcolor(red)7-12#
#color(white)(xxx)=9#

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