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How do solve the following linear system?: # x-4y=2 , x-7y=4 #?

1 Answer

Dec 28, 2015

#(-2/3,-2/3)#

Explanation:

Try to leave #x# alone in one side of the equation, then equate the other sides;

#x=2+4y , x=4+7y#

#2+4y=4+7y# #-># #-3y=2#
#y=-2/3#

Now, write #-2/3# instead of #y# in one of the equations, the value of #x# will be the same for both of them.

#x=2+4.(-2/3)# #-># #x=2-8/3#
#x=-2/3#

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