How do you solve the following system?: #x-5y=10, 2x+3y=11 #

1 Answer
Daksh S.
Jan 9, 2016

x=85/13 ; y=-9/13

Explanation:

#x-5y=10# ------- Eq. 1
#2x+3y=11#-------Eq. 2

There are numerous ways to solve this but I'll tell you easiest one.

Multiply both sides of Eq. 1 by 2
#2xx(x-5y)=2xx10# (Basically, we are trying to get the coefficient of x in both the equations to be same. You'll see why)

#2x-10y=20#-----Eq. 3

Subtract Eq. 2 from Eq. 3
#(2x-10y)-(2x+3y)=20-11#

(You see why?? Now the 2x have got cancelled and we are left with only y. That is why we get the coefficient of one variable same and subtract both the equations)

#-13y=9#
#y=-9/13#

Put this y in Eq. 1
#x-5(-9/13)=10#
#x+(45/13)=10#
#x=10-(45/13)#
#x=(130-45)/13#
#x=85/13#

Hence answer is #x=85/13 and y=-9/13#

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