#color(blue)("Using first principles")#
There are various ways of solving this question type. What follows is just one of them.
Given:
#7x-2y=4# ...............................Equation(1)
#5y+3x=10# ............................Equation(2)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Determine the value of "x)#
Consider equation (2)
Subtract #3x# from both sides giving:
#5y=10-3x#
Divide both sides by 5
#y=10/5-3/5x# ..............................Equation(3)
,~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Using equation(3) substitute for y in equation (1)
#color(brown)(7x-2y=4)color(blue)(" "->" "7x-2(10/5-3/5x)=4#
#=>7x-4+6/5x=4#
#41/5x-4=4#
Add 4 to both sides
#41/5x=8#
Multiply both sides by #5/41#
#color(blue)(=>x=5/41xx8" " =" "40/41)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Determine the value of ")#
#color(brown)("Using shortcuts method")#
Substitute #x=40/41# into equation(2)
#color(brown)(5y+3x=10color(blue)(" "->" "5y+3(40/41)=10))#
#y=58/41#