How do solve the following linear system?: $5 x + 2 y = 2, 4 x + 3 y = 29$ $5x+2y=2, 4x+3y=29$ ?

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Answer 1 · 2017-11-29T22:50:41

$x = - \frac{52}{7}$ $x=-52/7$ and $y = \frac{137}{7}$ $y=137/7$

$5 \cdot (4 x + 3 y) - 4 \cdot (5 x + 2 y) = 5 \cdot 29 - 4 \cdot 2$ $5*(4x+3y)-4*(5x+2y)=5*29-4*2$

$7 y = 137$ $7y=137$ , so $y = \frac{137}{7}$ $y=137/7$

Hence,

$5 x + 2 \cdot \frac{137}{7} = 2$ $5x+2*137/7=2$

$5 x = - \frac{260}{7}$ $5x=-260/7$ , so $x = - \frac{52}{7}$ $x=-52/7$

How do solve the following linear system?: 5x+2y=2, 4x+3y=29 5x+2y=2,4x+3y=29 5x+2y=2, 4x+3y=29 ?