How do you solve the following linear system $- x + 3 y = 2, x - 8 y = 2$ $-x + 3y = 2 , x -8y =2$ ?

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How do you solve the following linear system $- x + 3 y = 2, x - 8 y = 2$ $-x + 3y = 2 , x -8y =2$ ?

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Answer 1 · 2015-11-14T06:41:22

Using substitution, $x = - 4.4$ $x = -4.4$ and $y = - 0.8$ $y = -0.8$ .

Explanation:

You can use substitution.

Our first step is to isolate a variable to one side, so that we can plug it in for variable wherever. What I notice first is that we have a positive $x$ $x$ in the second equation. Therefore, I can add $8 y$ $8y$ to each side in order to isolate the $x$ $x$ . We now have $x = 2 + 8 y$ $x = 2 + 8y$ .

We can plug this into the first equation. $- (2 + 8 y) + 3 y = 2$ $-(2 + 8y) + 3y =2$ . By distributing we can get $- 2 - 8 y + 3 y = 2$ $-2 -8y + 3y =2$ . By solving out this equation, we end up with $y = 0.8$ $y = 0.8$ .

Now we can plug $y$ $y$ back into our equation that says $x = 2 + 8 y$ $x = 2 + 8y$ . So we can say that $x = 2 + 8 (- 0.8)$ $x = 2 + 8(-0.8)$ . That solves out to be $x = - 4.4$ $x = -4.4$ . We can plug this back into the original equations.

$- x + 3 y = 2 \Rightarrow - (- 4.4) + 3 (- 0.8) = 2$ $-x+3y =2 => -(-4.4) + 3(-0.8) = 2$
Then, $4.4 + - 2.4 = 2$ $4.4 + -2.4 = 2$ , and $2 = 2$ $2 =2$ .

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How do you solve the following linear system $- x + 3 y = 2, x - 8 y = 2$ $-x + 3y = 2 , x -8y =2$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do you solve the following linear system −x+3y=2,x−8y=2-x + 3y = 2 , x -8y =2 ?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve the following linear system $- x + 3 y = 2, x - 8 y = 2$ $-x + 3y = 2 , x -8y =2$ ?