How do you solve the following system: $3x + 8y = -2, x +4y = 16$ ?

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How do you solve the following system: $3x + 8y = -2, x +4y = 16$ ?

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Answer 1 · 2016-03-14T18:26:17

x = -34
$y = 25/2$

Explanation:

x + 4y = 16 --> x = 16 - 4y
Substitute x by (16 - 4y) into the second equation -->
3x + 8y = -2
3(16 - 4y) + 8y = - 2
48 - 12y + 8y = -2
-4y = - 2 - 48 = -50
$y = -50/-4 = 25/2$ --> $x = 16 - 4(25/2) = - 34$
Check
$3x + 8y = 3(-34) + 8(25/2) = - 102 + 100 = -2$ . OK

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How do you solve the following system: $3x + 8y = -2, x +4y = 16$ ?

1 Answer

Explanation:

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How do you solve the following system: $3x + 8y = -2, x +4y = 16$ ?