How do you solve the following system?: # 1/2x=y-1 , -x+3y=-7 #

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Answer 1 · 2018-04-24T05:07:32

#x=-20#

#y=-9#

The given equations are

# 1/2x = y-1#
# -x+3y = -7#

From #1/2x = y-1#

# x=2(y-1)#

Substituting this #x# value in equation #-x+3y = -7#

#=> - (2(y-1) + 3y = -7#

#=> -2y +2 +3y = -7#

#=> y+2 = -7#

#=> y= -7-2#

#=> y = -9#

Substitute this #y# value in any of the given equations to obtain the #x# value

#-x +3y = -7#

#=> -x + 3(-9) = -7#

#=> -x -27 = -7#

#=> x = -20 #