How do you solve the following system: #8x-3y=3, 5x+8y= -29 #?

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Answer 1 · 2017-07-24T07:56:58

Arrange equations, you will get #x=-63/79# and #y=-247/79#

Enlarge the first equation by 8 and the second equation by 3.

#64x - 24y = 24#
#15x + 24y = -87#

Now you have (after adding these equations):
#79x = -63#

Now you can have #x=-63/79#

Find y now after putting x value in the first original equation:

#8times(-63/79) -3y = 3#

#-3y = 3 + (504/79)#

#-3y = 741/79#

#y= -247/79#

Now you have y

#y=-247/79#