How do you solve the following system: $- 5 x + 3 y = 6, 4 x + 3 y = 36$ $-5x + 3y= 6, 4x+3y=36$ ?

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How do you solve the following system: $- 5 x + 3 y = 6, 4 x + 3 y = 36$ $-5x + 3y= 6, 4x+3y=36$ ?

1 Answer

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Answer 1 · 2016-03-30T11:09:01

$x = \frac{10}{3} and y = \frac{68}{9}$ $x=10/3 and y=68/9$

Explanation:

$- 5 x + 3 y = 6$ $-5x+3y=6$ (1)
$4 x + 3 y = 36$ $4x +3y= 36$ (2) Now subtracting (2) from(1) we get $- 9 x = - 30 or x = \frac{30}{9} = \frac{10}{3}$ $-9x=-30 or x=30/9=10/3$ Putting the value of x in equation (1) we get $3 y = 6 + 5 \cdot \frac{10}{3} or y = \frac{68}{9}$ $3y = 6+5*10/3 or y =68/9$ [ans]

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How do you solve the following system: $- 5 x + 3 y = 6, 4 x + 3 y = 36$ $-5x + 3y= 6, 4x+3y=36$ ?

1 Answer

Explanation:

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How do you solve the following system: -5x + 3y= 6, 4x+3y=36 −5x+3y=6,4x+3y=36-5x + 3y= 6, 4x+3y=36 ?

1 Answer

Explanation:

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How do you solve the following system: $- 5 x + 3 y = 6, 4 x + 3 y = 36$ $-5x + 3y= 6, 4x+3y=36$ ?