How do you solve the system of linear equations: $y = 4x - 3$ and $y = - 3x - 3$ ?

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How do you solve the system of linear equations: $y = 4x - 3$ and $y = - 3x - 3$ ?

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Answer 1 · 2015-11-14T00:02:55

I found:
$x=-3$
$y=0$

Explanation:

You can try substitute the first equation into the second for $y$ so that you get:
$color(red)(4x-3)=-3x-3$ solve for $x$ :
$7x=0$
$x=0/7=0$
substitute this into the first equation:
$y=4*color(red)(0)-3=-3$

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How do you solve the system of linear equations: $y = 4x - 3$ and $y = - 3x - 3$ ?

1 Answer

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Science

Math

Humanities

... and beyond

How do you solve the system of linear equations: y = 4x - 3y = 4x - 3 and y = - 3x - 3y = - 3x - 3?

1 Answer

Explanation:

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Impact of this question

How do you solve the system of linear equations: $y = 4x - 3$ and $y = - 3x - 3$ ?