How do you solve the system of linear equations: #y = 4x - 3# and #y = - 3x - 3#?

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How do you solve the system of linear equations: #y = 4x - 3# and #y = - 3x - 3#?

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Answer 1 · 2015-11-14T00:02:55

I found:
#x=-3#
#y=0#

Explanation:

You can try substitute the first equation into the second for #y# so that you get:
#color(red)(4x-3)=-3x-3# solve for #x#:
#7x=0#
#x=0/7=0#
substitute this into the first equation:
#y=4*color(red)(0)-3=-3#

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How do you solve the system of linear equations: #y = 4x - 3# and #y = - 3x - 3#?

1 Answer

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