How do you solve the following system?: $4x-y=-1 , 3x - 2y = 1$

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Answer 1 · 2018-05-14T15:35:22

$x=-3/5$ , $y= -7/5$

From the first equation, you have $y = 4x+1$ . Substitute in the second equation to get

$3x-2y=1 \iff 3x-2(4x+1)=1 \iff 3x-8x-2=1$

So, you have $-5x = 3$ and thus $x=-3/5$

Since we knew that $y = 4x+1$ , we have

$y = 4(-3/5)+1 = -12/5+1 = -7/5$

How do you solve the following system?: 4x-y=-1 , 3x - 2y = 1 4x-y=-1 , 3x - 2y = 1