How do solve the following linear system?: # 4x+y=6 , 7x-2y=-16 #?

1 Answer
Shwetank Mauria
Feb 22, 2016

Solution is #x=-4/15# and #y=106/15=7(1)/15#

Explanation:

For solving system of linear equations #4x+y=6# and #7x−2y=−16#, what is required is first eliminating one variable to get the value of another and then substituting second in either to get value of first variable.

For this, let us choose and get #y# from first equation #4x+y=6#, which gives, #y=6-4x#.

Now putting this in second equation #7x−2y=−16#, we get

#7x-2(6-4x)=-16# or #7x-12+8x=-16# or

#15x=12-16=-4#. Hence #x=-4/15#

Hence #y=6-4*(-4/15)# or #y=6+16/15=106/15#

Hence solution is #x=-4/15# and #y=106/15=7(1)/15#

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