How do you solve the following system?: $8 x - 2 y = - 4, - 4 x + 2 y = 2$ $8x - 2y = - 4 , -4x + 2y = 2$

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How do you solve the following system?: $8 x - 2 y = - 4, - 4 x + 2 y = 2$ $8x - 2y = - 4 , -4x + 2y = 2$

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Answer 1 · 2018-03-24T10:48:50

$(x, y) \to (- \frac{1}{2}, 0)$ $(x,y)to(-1/2,0)$

Explanation:

$8 x - 2 y = - 4 \to (1)$ $8xcolor(red)(-2y)=-4to(1)$

$- 4 x + 2 y = 2 \to (2)$ $-4xcolor(red)(+2y)=2to(2)$

$adding equations (1) and (2) eliminates the y-term$ $"adding equations "(1)" and "(2)" eliminates the y-term"$

$(1) + (2) term by term on both sides$ $(1)+(2)" term by term on both sides"$

$(8 x - 4 x) + (- 2 y + 2 y) = (- 4 + 2)$ $(8x-4x)+(-2y+2y)=(-4+2)$

$\Rightarrow 4 x = - 2$ $rArr4x=-2$

$divide both sides by 2$ $"divide both sides by 2"$

$(cancel(4) x)/cancel(4)=(-2)/4$

$rArrx=-1/2$

$"substitute "x=-1/2" into either of the 2 equations"$

$(2)rArr2+2y=2$

$rArr2y=2-2=0rArry=0$

$"the solution is "(x,y)to(-1/2,0)$

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How do you solve the following system?: $8 x - 2 y = - 4, - 4 x + 2 y = 2$ $8x - 2y = - 4 , -4x + 2y = 2$

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following system?: 8x - 2y = - 4 , -4x + 2y = 2 8x−2y=−4,−4x+2y=2 8x - 2y = - 4 , -4x + 2y = 2

1 Answer

Explanation:

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How do you solve the following system?: $8 x - 2 y = - 4, - 4 x + 2 y = 2$ $8x - 2y = - 4 , -4x + 2y = 2$