How do you solve $- 10 X - 3 Y = 3$ $-10X-3Y=3$ and $50 X + 15 Y = - 14$ $50X+15Y=-14$ ?

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How do you solve $- 10 X - 3 Y = 3$ $-10X-3Y=3$ and $50 X + 15 Y = - 14$ $50X+15Y=-14$ ?

1 Answer

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Answer 1 · 2015-06-27T02:40:09

There is no "solution" for this pair of equations; they represent two parallel lines (they do not intersect).

Explanation:

If you multiply $- 10 X - 3 Y = 3$ $-10X-3Y=3$ by $(- 5)$ $(-5)$ you get
$50 X + 15 Y = - 15$ $50X+15Y = -15$
comparing this to the second given equation
$50 X + 15 Y = - 14$ $50X+15Y = -14$
we see that the left sides (containing all the variables) are identical
but the right side have different constant values.
Therefore the lines are parallel but not identical.

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How do you solve $- 10 X - 3 Y = 3$ $-10X-3Y=3$ and $50 X + 15 Y = - 14$ $50X+15Y=-14$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you solve -10X-3Y=3−10X−3Y=3-10X-3Y=3 and 50X+15Y=-1450X+15Y=−1450X+15Y=-14?

1 Answer

Explanation:

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How do you solve $- 10 X - 3 Y = 3$ $-10X-3Y=3$ and $50 X + 15 Y = - 14$ $50X+15Y=-14$ ?