How do you solve the following system: $7y − 6x − 5 = 0, 7y - 2x = 10$ ?

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Answer 1 · 2017-03-11T16:49:50

$x=0.8$

$7y - 6x - 5=0$ (+5)
$7y-2x=10$

$7y - 6x = 5$
$7y - 2x = 10$

subtract:

$-4x = -5$

divide by $4$ :
$-x = -0.8$

multiply by $-1$ :
$x = 0.8$

How do you solve the following system: 7y − 6x − 5 = 0, 7y - 2x = 10 7y − 6x − 5 = 0, 7y - 2x = 10 ?