How do you solve the following linear system $2x - 6y = 2, 3x - 8y = 2$ ?

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How do you solve the following linear system $2x - 6y = 2, 3x - 8y = 2$ ?

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Answer 1 · 2018-03-18T20:21:04

see below

Explanation:

`We have, $2x-6y=2$ or $x=(2+6y)//2$ or $x=1+3y$ .
The second equation is $3x=2+8y$ .
Substituting the value of $x$ in $2nd$ equation,we get,
$3 xx(1+3y)=2+8y$
Or, $3+9y-8y-2=0$
Or, $1+y=0$
Thus, $y=-1$
Putting this value in the $1st$ equation, we get,
$x=1-3$ or $x=-2$

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How do you solve the following linear system $2x - 6y = 2, 3x - 8y = 2$ ?

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Science

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Humanities

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How do you solve the following linear system 2x - 6y = 2, 3x - 8y = 2 2x - 6y = 2, 3x - 8y = 2 ?

1 Answer

Explanation:

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How do you solve the following linear system $2x - 6y = 2, 3x - 8y = 2$ ?