How do you solve $y=x-4$ and $4x+y=26$ using substitution?

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Answer 1 · 2016-03-16T22:03:32

$x=6$

$y=x-4$
$26=4x+y$

If $y=y$ , then we can rewrite this system as this: $4x+x-4=26$ .

Then we combine like terms and add $4$ on both sides to give us $5x=30$ . Divide by $5$ on both sides and we arrive at the solution: $x=6$

How do you solve y=x-4y=x-4 and 4x+y=264x+y=26 using substitution?