How do you solve 4y-4x=4 and 4y-4x=12?

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Answer 1 · 2018-06-26T13:15:55

No solution.

Please observe that in both the equations

$4y-4x=4$ and $4y-4x=12$ ,

$LHS$ is same, but $RHS$ is different.

Such equations represent incongruity

and in such cases we do not have any solutions.

When we draw a graph of any pair of linear equations,

the solution is given by point of their intersection.

When we do not have any solution,

it means lines do not intersect at all and

in other words they are parallel when drawn on graph.

In given case, graph appears as

graph{(4y-4x-4)(4y-4x-12)=0 [-10, 10, -5, 5]}