How do you solve $x + 2 y = 7$ $x + 2y = 7$ and $2 x - 3 y = - 5$ $2x - 3y = -5$ ?

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How do you solve $x + 2 y = 7$ $x + 2y = 7$ and $2 x - 3 y = - 5$ $2x - 3y = -5$ ?

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Answer 1 · 2016-06-05T12:00:08

You could solve using substitution.

Explanation:

$x + 2 y = 7$ $x + 2y = 7$
$2 x - 3 y = - 5$ $2x -3y = -5$

We can take one of these equations and solve for one variable, and plug that into the variable in the other equation. Let's use the first equation.

$x + 2 y = 7$ $x + 2y = 7$ (We are solving for x)
$x = 7 - 2 y$ $x = 7 - 2y$ (We now have $x$ $x$ , so we can plug this into $x$ $x$ in the other equation)

$2 x - 3 y = - 5$ $2x - 3y =-5$
$2 (7 - 2 y) - 3 y = - 5$ $2(7 - 2y) - 3y =-5$ (Plug in $7 - 2 x$ $7 - 2x$ from the other equation)
$14 - 4 y - 3 y = - 5$ $14 - 4y -3y = -5$ (Distribute)
$- 7 y = - 19$ $-7y = -19$
$y = \frac{19}{7}$ $y = 19/7$ (We have the solution for $y$ $y$ , time to find $x$ $x$ )

$x + 2 (\frac{19}{7}) = 7$ $x + 2(19/7) = 7$ (Plug in $y$ $y$ )
$x + \frac{38}{7} = 7$ $x + 38/7 = 7$
$x = \frac{11}{7}$ $x = 11/7$ (We have the x value)

The solutions are: $x = \frac{11}{7}$ $x = 11/7$ , and $y = \frac{19}{7}$ $y = 19/7$ .

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How do you solve $x + 2 y = 7$ $x + 2y = 7$ and $2 x - 3 y = - 5$ $2x - 3y = -5$ ?

1 Answer

Explanation:

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How do you solve x + 2y = 7x+2y=7x + 2y = 7 and 2x - 3y = -52x−3y=−52x - 3y = -5?

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How do you solve $x + 2 y = 7$ $x + 2y = 7$ and $2 x - 3 y = - 5$ $2x - 3y = -5$ ?