How do you solve the system of equations $- 4 x + 5 y = 6$ $-4x + 5y = 6$ and $3 x + y = - 14$ $3x + y = - 14$ ?

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Answer 1 · 2018-05-09T04:10:43

$x = - 4, y = - 2$ $color(purple)(x = -4, y = -2$

$- 4 x + 5 y = 6, Eqn (1)$ $-4x + 5y = 6, " Eqn (1)"$

$3 x + y = - 14, Eqn (2)$ $3x + y = -14, " Eqn (2)"$

$- 15 x - 5 y = 70, Eqn (2) * -5$ $-15x - 5y = 70, " Eqn (2) * -5"$

$Adding Eqn (1) and En (2) * -5$ $"Adding Eqn (1) and En (2) * -5"$ ,

$- 19 x = 76$ $-19x = 76$

$x = - \frac{76}{19} = - 4$ $color(purple)(x = -76/19 = -4$

$"Substituting value of x in Eqn (1)'$ ,

$16 + 5y = 6$

$color(purple)(y = (6-16)/5 = -2$

How do you solve the system of equations -4x + 5y = 6−4x+5y=6-4x + 5y = 6 and 3x + y = - 143x+y=−143x + y = - 14?