How do you solve the following system using substitution?: #-3x + 3y= 3, -5x + y = 13#

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Answer 1 · 2015-10-26T01:23:19

#x=-3#
#y=-2#

First, isolate #y# in the first equation.

#color(blue)([1])" "-3x+3y=3#

#color(blue)([2])" "3y=3+3x#

#color(blue)([3])" "y=1+x#

Now substitute the value of #y# in the first equation to #y# in the second equation.

#color(red)([1])" "-5x+color(blue)(y)=13#

#color(red)([2])" "-5x+color(blue)((1+x))=13#

#color(red)([3])" "-4x=12#

#color(red)([4])" "x=-3#

Now that we have the value of #x#, we will simply substitute this to the first equation.

#color(blue)([4])" "y=1+(-3)#

#color(blue)([5])" "y=-2#