How do you solve $4 x + y = 8$ $4x + y = 8$ and $y = 4 x$ $y = 4x$ using substitution?

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Answer 1 · 2016-07-20T21:41:51

$x = 1, y = 4$ $x = 1, y = 4$

The y values in both equations are the same.
MAke y the subject in each equation.

$y = - 4 x + 8 and y = 4 x$ $y = -4x+8" and " y = 4x$

Now, $y = \subset s t f or e a c h y$ $" "y " " = subst for each "y$

$:. -4x +8 = 4x$

$8 = 8x$

$x=1$

If $x= 1$ , then $y = 4 xx1 = 4$

How do you solve 4x + y = 84x+y=84x + y = 8 and y = 4xy=4xy = 4x using substitution?