How do solve the following linear system?: $2 x + 5 y = 1, - 6 x - 2 y = - 8$ $2x+5y=1 , -6x-2y=-8$ ?

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Answer 1 · 2018-06-06T18:37:09

$x = \frac{19}{13}$ $x=19/13$ and $y = - \frac{5}{13}$ $y=-5/13$

$2 \cdot (2 x + 5 y) + 5 \cdot (- 6 x - 2 y) = 2 \cdot 1 + 5 \cdot (- 8)$ $2*(2x+5y)+5*(-6x-2y)=2*1+5*(-8)$

$4 x + 10 y - 30 x - 10 y = 2 - 40$ $4x+10y-30x-10y=2-40$

$- 26 x = - 38$ $-26x=-38$

So, $x = \frac{- 38}{- 26} = \frac{19}{13}$ $x=(-38)/(-26)=19/13$

Hence,

$2 \cdot \frac{19}{13} + 5 y = 1$ $2*19/13+5y=1$

$\frac{38}{13} + 5 y = 1$ $38/13+5y=1$

$5 y = - \frac{25}{13}$ $5y=-25/13$ , thus $y = - \frac{5}{13}$ $y=-5/13$

How do solve the following linear system?: 2x+5y=1 , -6x-2y=-8 2x+5y=1,−6x−2y=−8 2x+5y=1 , -6x-2y=-8 ?