How do you solve #x= y - 2# and #3x - y = 6# using substitution?

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Answer 1 · 2018-03-12T12:23:08

#color(magenta)(x=4 and y=6#

#x=(y-2)#

Given that,

#3x-y=6#

Replacing #x=(y-2)#

#3(y-2)-y=6#

Opening the brackets:

#3y-6-y=6#

#3y-y=6+6#

#2y=12#

#y=12/2#

#color(red)(y=6#

#x=(y-2)#

#x=6-2#

#color(red)(x=4#

#therefore# #color(magenta)(x=4 and y=6#

~Hope this helps! :)