How do you solve #3x - 2y = 0# and #x + y = -5# using substitution?

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Answer 1 · 2016-04-11T04:49:00

#x=-2#
#y=-3#

Given -

#3x-2y=0# --------- (1)
#x+y=-5# ------------(2)

Solve equation (2) for #x#

#y=-5-x#

Substitute #y=-5-x# in equation (1)

#3x-2(-5-x)=0#
#3x+10+2x=0#
#5x=-10#
#x=-2#

Substitute #x=-2# in equation (1)

#-2+y=-5#
#y=-5+2#
#y=-3#