How do you solve $3 x - 2 y = 0$ $3x - 2y = 0$ and $x + y = - 5$ $x + y = -5$ using substitution?

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Answer 1 · 2016-04-11T04:49:00

$x = - 2$ $x=-2$
$y = - 3$ $y=-3$

Given -

$3 x - 2 y = 0$ $3x-2y=0$ --------- (1)
$x + y = - 5$ $x+y=-5$ ------------(2)

Solve equation (2) for $x$ $x$

$y = - 5 - x$ $y=-5-x$

Substitute $y = - 5 - x$ $y=-5-x$ in equation (1)

$3 x - 2 (- 5 - x) = 0$ $3x-2(-5-x)=0$
$3 x + 10 + 2 x = 0$ $3x+10+2x=0$
$5 x = - 10$ $5x=-10$
$x = - 2$ $x=-2$

Substitute $x = - 2$ $x=-2$ in equation (1)

$- 2 + y = - 5$ $-2+y=-5$
$y = - 5 + 2$ $y=-5+2$
$y = - 3$ $y=-3$

How do you solve 3x−2y=03x - 2y = 0 and x+y=−5x + y = -5 using substitution?