How do you solve the system y = -3x + 6 and 3x-y = 6?

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How do you solve the system y = -3x + 6 and 3x-y = 6?

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Answer 1 · 2016-01-14T11:12:58

$x = 2$ $x=2$
$y = 0$ $y=0$

Explanation:

The equations are

$y = - 3 x + 6$ $y=-3x+6$
$3 x - y = 6$ $3x-y=6$

Solve the value of $x$ $x$ by substitution

$3 x - y = 6$ $3x-y=6$
$3 x - (- 3 x + 6) = 6$ $3x-(-3x+6)=6$ , plug in the value of y
$3 x + 3 x - 6 = 6$ $3x+3x-6=6$ , simplify and combine like terms
$6 x = 12$ $6x=12$ , isolate x
$(cancel6x)/cancel6=12/6$
$x=2$

To find the value of $y$ , where

$y=-3x+6$ , plug in the value of x
$y=-3(2)+6$ , simplify
$y=-6+6$
$y=0$

Checking:

$y=-3x+6$
$0=-3(2)+6$
$0=-6+6$
$0=0$
$3x-y=6$
$3(2)-0=6$
$6-0=6$
$6=6$

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How do you solve the system y = -3x + 6 and 3x-y = 6?

1 Answer

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