How do you solve the following system: #x-2y=3, 6y + 4x = 12 #?

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Answer 1 · 2016-05-20T10:52:23

The solution for the system of equations is:
#color(green)(x = 3 #

#color(green)(y=0#

#x - 2y = 3#, multiplying the equation by #4#

#color(blue)(4x) - 8y = 12#...........equation #(1)#

#color(blue)(4x) + 6y =12#............equation #(2)#

Solving by elimination:

Subtracting equation #2# from equation #1#:

#cancelcolor(blue)(4x) - 8y = cancel12#
#-cancelcolor(blue)(4x)- 6y = cancel(-12)#

#-14y =0#

#y = 0/(-14)#

#color(green)(y=0#

Finding #x# from equation #1:#

#x - 2y = 3#

#x = 3 + 2y #

#x = 3 + 2 xx 0 #

#x = 3 + 0 #

#color(green)(x = 3 #